Finite Math Examples

$G = 16 - \frac{D}{20}$

Step 1

Rewrite the equation as $16 - \frac{D}{20} = G$ .

$16 - \frac{D}{20} = G$

Step 2

Subtract $16$ from both sides of the equation.

$- \frac{D}{20} = G - 16$

Step 3

Multiply both sides of the equation by $- 20$ .

$- 20 (- \frac{D}{20}) = - 20 (G - 16)$

Step 4

Simplify both sides of the equation.

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Step 4.1

Simplify the left side.

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Step 4.1.1

Simplify $- 20 (- \frac{D}{20})$ .

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Step 4.1.1.1

Cancel the common factor of $20$ .

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Step 4.1.1.1.1

Move the leading negative in $- \frac{D}{20}$ into the numerator.

$- 20 \frac{- D}{20} = - 20 (G - 16)$

Step 4.1.1.1.2

Factor $20$ out of $- 20$ .

$20 (- 1) \frac{- D}{20} = - 20 (G - 16)$

Step 4.1.1.1.3

Cancel the common factor.

$20 \cdot - 1 \frac{- D}{20} = - 20 (G - 16)$

Step 4.1.1.1.4

Rewrite the expression.

$- - D = - 20 (G - 16)$

$- - D = - 20 (G - 16)$

Step 4.1.1.2

Multiply.

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Step 4.1.1.2.1

Multiply $- 1$ by $- 1$ .

$1 D = - 20 (G - 16)$

Step 4.1.1.2.2

Multiply $D$ by $1$ .

$D = - 20 (G - 16)$

$D = - 20 (G - 16)$

$D = - 20 (G - 16)$

$D = - 20 (G - 16)$

Step 4.2

Simplify the right side.

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Step 4.2.1

Simplify $- 20 (G - 16)$ .

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Step 4.2.1.1

Apply the distributive property.

$D = - 20 G - 20 \cdot - 16$

Step 4.2.1.2

Multiply $- 20$ by $- 16$ .

$D = - 20 G + 320$

$D = - 20 G + 320$

$D = - 20 G + 320$

$D = - 20 G + 320$

$[\begin{array}{c} x^{2} & \frac{1}{2} \\ \sqrt{π} & \int x d x \end{array}]$